Question

if a and b are the zeroes of the polynomial p(x)=ax2 + bx +c, find the value of a2/b + b2/a

Answer 1

Answer:

Step-by-step explanation:

alpha and beta are the zeroes of the quadratic polynomial p(x)=ax2+bx+c then ... If alpha,beta are roots of a quadratic equation ax^2+bx+c=0,then ... α+β=-b/a αβ=c/a α²+β²=(α+β)²-2αβ= = \frac{b^2}{a^2}

Answer 2

Answer:

b2-2ac/a2

Step-by-step explanation:

The polynomial is x2+bx+c

Sum of zeroes = a + B = -b/a

Product of zeroes = aB = c/a

Therefore, a2 - B2 = (a + B)2 - 2aB

= (-b/a)2 - 2×c/a

= b2/a2 - 2c/a

= b2 - 2ac / a2

Thank you.........