Solve the question 1÷√7+√6-√3
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Answer:
Step-by-step explanation:
Answer:
\frac{1}{\sqrt{7}- \sqrt{6}}= (\sqrt{7}+\sqrt{6})
Step-by-step explanation:
Given \frac{1}{\sqrt{7}- \sqrt{6}}
Multiply numerator and denominator by (√7+√6), we get
= \frac{(\sqrt{7}+\sqrt{6})}</p><p>{(\sqrt{7}-\sqrt{6})(\sqrt{7}+\sqrt{6})}
\* By algebraic identity:
(a+b)(a-b) = a²-b²
= \frac{(\sqrt{7}+\sqrt{6})}{(\sqrt{7})^{2}-(\sqrt{6})^{2}}
= \frac{(\sqrt{7}+\sqrt{6})}{7-6}
= (\sqrt{7}+\sqrt{6})
Therefore,
\frac{1}{\sqrt{7}- \sqrt{6}}= (\sqrt{7}+\sqrt{6})
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