number of seven digited numbers, with sum of digits equal to 10 and formed by using the digits 1,2 and 3 only is
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Answered by
2
3+2+1+1+1+1+1=10(3211111)
This can be furtur rearranged as:
3111112
3111121
3111211
3112111
3121111
2111113
2111131
and so on...
This can be furtur rearranged as:
3111112
3111121
3111211
3112111
3121111
2111113
2111131
and so on...
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Answered by
0
The digt are 3,1,2
Number are....
3211111
3111112
3121111
3112111
3111211
3111121
2311111
2131111
2113111
2111311
2111131
2111113
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