Question

Number of sp³ hybrid orbitals are present in CH²=CH—CH²—NH² is​

Answer 1

Answer:

Lcm 108,96,72,54,36

Explanation:

Lcm 108,96,72,54,36

Answer 2

Answer:

I hope this answer is write

Explanation:

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How many sigma and pi bonds are present in the molecule given below:

CH

2

=C=CH−CH

3

A

sigma C−C bonds =5, sigma C−H bonds =5, pi C−C bonds =4

B

sigma C−C bonds =3, sigma C−H bonds =6, pi C−C bonds =2

C

sigma C−C bonds =4, sigma C−H bonds =5, pi C−C bonds =2

D

sigma C−C bonds =4, sigma C−H bonds =6, pi C−C bonds =4

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Solution

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Correct option is

B

sigma C−C bonds =3, sigma C−H bonds =6, pi C−C bonds =2

Sigma bonds (σ) are formed by the coaxial overlapping of the two orbitals of equal energies. Generally, the single bonds are sigma bonds.

Pi bonds (π) are formed by the lateral overlapping of two orbitals with equal energies.

Double bond contains one sigma bond and one pi bond whereas triple bond contains one sigma bond and two pi bond.

Here,

sigma C−C bonds =3, sigma C−H bonds =2+1+3=6 , pi C−C bonds =1+1=2

Hence, option B is correct.