number of sulphur atoms present in a sample of mass 556amu of percentage composition of sulphur is 11.51%.
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Given that the compound contains 0.032% of sulphur by mass.
Let the molecular mass of compound be 'X'.
Atomic mass of sulphur- 32g
atomic mass of 2 sulphur atoms= (32*2)g
since 0.032 % sulphur is present in the given compound,
percentage of sulphur * total molecular weight of compound = weight of sulphur in compound.
0.032 % of X = 32*2
(0.032 / 100) * X = 64
X = (64 * 100)/ 0.032
X = 2 * 10^5 g
Ans:- The molecular weight of the compound is 2 * 10^5 g
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Let the molecular mass of compound be 'X'.
Atomic mass of sulphur- 32g
atomic mass of 2 sulphur atoms= (32*2)g
since 0.032 % sulphur is present in the given compound,
percentage of sulphur * total molecular weight of compound = weight of sulphur in compound.
0.032 % of X = 32*2
(0.032 / 100) * X = 64
X = (64 * 100)/ 0.032
X = 2 * 10^5 g
Ans:- The molecular weight of the compound is 2 * 10^5 g
please mark me as brainliest
tuka81:
please mark me brainliest because I answered the question first
Answered by
7
Given that the compound contains 0.032% of sulphur by mass.
Let the molecular mass of compound be 'X'.
Atomic mass of sulphur- 32g
atomic mass of 2 sulphur atoms= (32*2)g
since 0.032 % sulphur is present in the given compound,
percentage of sulphur * total molecular weight of compound = weight of sulphur in compound.
0.032 % of X = 32*2
(0.032 / 100) * X = 64
X = (64 * 100)/ 0.032
X = 2 * 10^5 g
Ans:- The molecular weight of the compound is 2 * 10^5 g
Let the molecular mass of compound be 'X'.
Atomic mass of sulphur- 32g
atomic mass of 2 sulphur atoms= (32*2)g
since 0.032 % sulphur is present in the given compound,
percentage of sulphur * total molecular weight of compound = weight of sulphur in compound.
0.032 % of X = 32*2
(0.032 / 100) * X = 64
X = (64 * 100)/ 0.032
X = 2 * 10^5 g
Ans:- The molecular weight of the compound is 2 * 10^5 g
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