Math, asked by radhanakumari40, 8 months ago

Number of term in the AP 3,7,11....99is
A.33
B.25
c.96
d.95

Answers

Answered by AadiDMAN
0

Answer:

25

Step-by-step explanation:

a=3

d=7-3=4

an=99

an=a+(n-1)d

99=3+(n-1)4

99=3+4n-4

99=4n-1

4n=100

n=25

Answered by Mounikamaddula
0

Answer:

Option B is the correct answer....

a=3, d=4, an=99

Now, an=a+(n-1)d

99=3+(n-1)4

99=3+4n-4

99=4n-1

4n=100

n=100/4=25

The n value is 25...

Step-by-step explanation:

Hope it helps you frnd.......

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