Question

Number of unit cell present in 1.17g of nacl

Answer 1

Answer:

The number of Cl- ions present in one unit cell = 6×1/2 + 8×1/8 = 4 atoms per unit cell. So, each unit cell has 4 atoms of each Na+ and Cl-. Hence there are total 4 molecules of NaCl in each unit cell. As the mass of -Avogadro number of molecules- of NaCl is 58.5g.

Explanation:

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