Question

Number of valence electrons in 4.2 grams of n3-(nitride) ion

Answer 1

hey here is your answer


Given mass = 4.2gm
molar mass of N^3- = N+N+N = 42
therefore
no of moles of nitride ion = given mass/molecular mass

= 4.2/42
= 0.1 moles

no of valence electron in one nitrogen is = 5
then ,
no of valence electron in nitride ion is = 5+5+5+1 = 16

therefore

total no of valence electron in 4.3 gm of nitride N^3- = no of moles of nitride ion * no of valence electron present in one nitride ion * Avogadro number
= 0.1 × 16 × 6.022 × 10^23
= 1.6 × 6.022×10^23
= 9.6352 × 10^23
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