Question

number of zeros of p(x)=x^3-2x^2 is........
answer is 2
please show the method

Answer 1

here taking xcube to another side
x3=2x2
from here one answer is this is true only when x=0
further x=2
because x2will cutx2

Answer 2

given,p(x)=x^3-2x^2
for finding zeroes,let p(x)=0
~x^3-2x^2=0
~x^2(x-2)=0
~x^2=0 (or) (x-2)=0
~x=0 (or) x=2
hence,p(x) is said to have 2 zeroes