Question

Number series:
1,12,36,80,150,___?
1)299
2)304
3)252
4)656​

Answer 1

Answer:

$\huge\bigstar\underbrace{\mathtt\red{A} \mathtt\purple{N} \mathtt\green{S}\mathtt\blue{W} \mathtt\blue{E} \mathtt\orange{R}}\bigstar$

$\huge{\underline{\underline{\mathbb{ \color{violet}{ \: \: OPTION-C \: \: }}}}}$

Step-by-step explanation:

$\huge\sf{\pink{\fbox{\blue{\fbox{\purple{\fbox{\pink{Question:}}}}}}}}$

2,12,36,80,150,?

$\huge\red{\underline\orange{\underline\purple{To\: find:}}}$

? [6th term]

$\huge\red{\underline\orange{\underline\purple{Concept:}}}$

The series is in the form of $x^2+x^3$

Substitute x=1,2,3,etc.

$1^2+1^3$= 2

$2^2+2^3$ =12

$3^2+3^3$ = 36

$4^2+4^3$ = 80

$5^2+5^3$ = 150

$6^2+6^3$ = 252

Answer is Option C.......