number when divided by 340 gives a remainder 47. What would be the remainder when the same number is divided by 17 ?
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Secondary School Math 13 points
A no when divided by 342 gives a remainder 47. when the same no. divided by 19 what would be the remainder
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As per statement 1,
The number must be of the form 342k + 47 , where k is any integer
(Try recalling what you read in younger classes, i.e.
Dividend=Divisior*Quotient+Remainder)
Here;
Dividend is the number itself
Divisior is 342
Remainder is 47
Quotient obviously would be any integer (let it be k)
Now, further
342k + 47 = 19*18k + (38+9)
= 19*18k + 19*2 + 9
(19*2 when divided by 19 gives the quotient 2)
= 19*(18k+2) + 9
= 19m + 9 (here m is any other integer)
Now again recall that
Dividend=Divisior*Quotient+Remainder
Here;
Dividend is the number itself
Divisior is 19
Quotient is m (obviously an integer)
Remainder is 9....!!
Hope this helps you with your problem...!!
Cheers...!
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The answer is 13
GIVEN
Number when divided by 340 gives a remainder 47.
TO FIND
What would be the remainder when the same number is divided by 17 ?
SOLUTION
The above problem can be simply solved as follows;
Given,
Remainder when a number is divided by 340 = 47
Let the quotient = K
According to remainder formula;
Dividend = Divisor x Quotient + Remainder
= 340 × K + 47
The number = 340K + 47
= 17 × 20k + 17 × 2 + 13
= 17(20k + 2) + 13
Comparing with remainder formula
Divisor = 19
Quotient = 20k + 2
Remainder = 13
Hence, The answer is 13
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