numerator of a rational number is 7 less than the denominator .If the denominator is increased by 9 the numerator by 2 we get the same rational number find the number?
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let take that
denominator as 'X' then
numerator ' X-7'
after increasing ,
denominator x+9
numerator x-7+2 = x-5
x-5/x+9 = x-7/x
( cross multiplication)
x(x-5) =( x-7)(x+9)
x²-5x = x(x+9)-7(x+9)
x² -5x = x²+9x-7x -63
x²-5x = x²+2x - 63
x²-x²-5x-2x+63 = 0
-7x +63 = 0
-7x = -63
x = -63/-7
x = 9
by putting value of x in
denominator = x = 9
numerator = x-7 = 9-7 = 2
so the number is " 2/9 "
this is your answer
denominator as 'X' then
numerator ' X-7'
after increasing ,
denominator x+9
numerator x-7+2 = x-5
x-5/x+9 = x-7/x
( cross multiplication)
x(x-5) =( x-7)(x+9)
x²-5x = x(x+9)-7(x+9)
x² -5x = x²+9x-7x -63
x²-5x = x²+2x - 63
x²-x²-5x-2x+63 = 0
-7x +63 = 0
-7x = -63
x = -63/-7
x = 9
by putting value of x in
denominator = x = 9
numerator = x-7 = 9-7 = 2
so the number is " 2/9 "
this is your answer
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