Question

Numerical=A force 20N acts on a body of mass 5kg find acceleration produced.

Answer 1

${\bigstar\:{\pmb{\sf{\underline{Answer...}}}}}$

⋆ When a force of 20 N acts on a body of mass 5 kg then 4 m/s sq. is the rate of acceleration produced.

${\bigstar\:{\pmb{\sf{\underline{Provided \: that...}}}}}$

⋆ Given that: Force = 20 Newton

⋆ Given that: Mass = 5 kilograms

⋆ To find: Acceleration

${\bigstar\:{\pmb{\sf{\underline{Knowledge \: required...}}}}}$

⋆ To solve this question we have to use the Newton's second law of motion formula that is of force.

$\qquad \sf Force \: = Mass \times Acceleration \: \green \star$

${\bigstar\:{\pmb{\sf{\underline{Full \: Solution...}}}}}$

${\sf{:\implies Force \: = Mass \times Acceleration}}$

${\sf{:\implies 20 = 5 \times Acceleration}}$

${\sf{:\implies 20/5 \: = Acceleration}}$

${\sf{:\implies 4 \: = Acceleration}}$

${\sf{:\implies Acceleration \: = 4 \: ms^{-2}}}$

Henceforth, 4 m/s² is the acceleration.

Answer 2

Answer:

Explanation:

According to Newton's second law of motion,

Force applied (F) will be the product of mass and acceleration.

Let 'm' be the mass of the object and 'v' be the velocity, then it can be expressed as,

$F = ma$   ...(1)

From the question,

$m = 5\ kg$

$F = 20\ N$

By rearranging equation(1),

$a = \frac{F}{m}$

Substitute these values into the above equation,

$a = \frac{20}{5} = 4\ m/s^{2}$