Question

What will be the gas if The volume of 8g gas at stp is 2800ml

Answer 1

Explanation:

Number of moles of O

2

=

32

8

=

4

1

=0.25

Volume of 1 mol of O

2

at STP =22.4 L

∴ Volume of 0.25 mol of O

2

at STP =22.4×0.25=5.6 L