Question

numerical. A force of 30N is applied at a Perpendicular distance of 6 m form a pivot. what is the Moment?​

Answer 1

Correct Question :-

Numerical :-

A force of 30N is applied at a Perpendicular distance of 6 m form a pivot. what is the Moment?

Answer :

Explanation :-

To Find,

• The moment of force.

Solution,

Given that,

• Force applied = 30N
• Perpendicular distance from pivot = 6m

As we know that,

$\dag \: \: \underline{\boxed{ \red{ \sf{Moment \: of \: force = F \times d}}}}$

Where,

• F = Force
• d = Distance

According the question,

➨ Moment of force = 30N × 6m

➨ Moment of force = 180 Nm

The moment of force is 180 Newton metre.

More Information

• 1 Nm = 10⁷ dyne cm
• 1 kgf m = 9.8 Nm
• 1 Nm = 1kg m s·²
• 1 N = 10⁵ dyne
• The S.I. unit of distance is metre (m).
• The S.I. unit of Force is Newton (N).
• The S.I. unit of moment of force is Newton metre (Nm).