Question

Numerical Problem 1
A car, initially at rest, picks up a velocity of 72 kmh-!, over a distance of 25 m. Calculate
(i) acceleration of car (ii) time in which it picks up above velocity.
Solution​

Answer 1

Answer:

I) 8 m/s^2 II) 2.5 s

Step-by-step explanation:

Here,

u = 0 m/s

v = 72 km/h = 72*1000/3600 m/s = 20 m/s

S = 25 m

a = ?

t = ?

Using v^2 = u^2 + 2aS, we get

20^2 = 0^2 + 2 * a * 25

or a = 400/50

or a = 8 m/s^2

Again, using v = u + at, we get

20 = 0 + 8*t

or t = 20/8

or t = 2.5 s

Source: gostudy24