Numerical questions of physics
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% error = change of value /actual value × 100
now,
1) ℅ error ={ (7.4 -7.6)/7.6} × 100
= -200/76
= -2.63 %
2) % error ={(97.8-99.4)/99.4}× 100
={(-1.6)/99.4} × 100
=-1600/994
=-1 .6 ℅
3) % error = {(320 -332)/332 }× 100
= {-12/332} ×100
= -1200/332
= -3.61 ℅
now,
1) ℅ error ={ (7.4 -7.6)/7.6} × 100
= -200/76
= -2.63 %
2) % error ={(97.8-99.4)/99.4}× 100
={(-1.6)/99.4} × 100
=-1600/994
=-1 .6 ℅
3) % error = {(320 -332)/332 }× 100
= {-12/332} ×100
= -1200/332
= -3.61 ℅
kvnmurty:
should the values be mentioned as - 2.6% , - 1.6% ?
- 3.6%
yes !! you are right
because , % error = ( experimental -actual)/actual × 100
but here not mentioned sign
Answered by
4
1. % error = (7.4-7.6)/7.6 * 100 = - 20/7.6 = -2.6%. Magnitude = 2.6%
2. % error = (97.8 - 99.4)/99.4 *100 = - 1.6% Magnitude = 1.6%
3. % error = (320 - 332)/336 * 100 = - 3.6 % Magnitude = 2.6%
2. % error = (97.8 - 99.4)/99.4 *100 = - 1.6% Magnitude = 1.6%
3. % error = (320 - 332)/336 * 100 = - 3.6 % Magnitude = 2.6%
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