Question

Numericals :
1. A body starts from rest with a uniform acceleration
of 2 m s-2. Find the distance covered by the body
in 2 s.
Ans. 4 m
54​

Answer 1

Answer :

• Body will cover a distance of 4 metres .

Explanation :

• initial velocity of body, u = 0

( since,Body starts from rest)

• uniform acceleration of body, a = 2 ms⁻²
• time for which body travels, t = 2 s

we need to find ,

• distance covered by body , s = ?

So,

Using second equation of motion

→ s = u t + 1/2 a t²

[ where s is distance covered, u is initial velocity, a is acceleration and t is time taken ]

→ s =  u t + 1/2 a t²

[ putting known values ]

→ s = ( 0 ) ( 2 ) + 1/2 ( 2 ) ( 2 )²

→ s = 0 + 1/2 ( 2 ) ( 4 )

→ s = 4 m

therefore,

• The body will cover a distance of 4 metres .

Three equations of motion are as follows :

• First equation of motion

     v = u + a t

• second equation of motion

     s =  u t + 1/2 a t²

• third equation of motion

     2 a s = v² - u²

[ where s is distance covered, u is initial velocity, a is acceleration and t is time taken and v is final velocity of body]

Answer 2

Question:

A body starts from rest with a uniform acceleration of 2 m s-². Find the distance covered by the body in 2 s.

Answer:

Distance covered by the body is 4 m.

Step-by-step explanation:

As per given question we have; initial velocity of the body is 0 m/s, acceleration of the body is 2 m/s² and time taken is 2 s.

Using second equation of motion i.e.

s = u t + 1/2 a t²

From above data .. u is 0 m/s, a is 2 m/s² and t is 2 s.

Substitute the values,

→ s =  ut + 1/2 at²

→ s = (0)(2) + 1/2 × (2)(2)²

→ s = 0 + 1/2 × 2 × 4

→ s = 0 + 1/1 × 4

→ s = 4

Hence the distance covered by the body in 2 s is 4 m.