Numericals
1. A cubical box has sides measuring 20cm each. It exerts a force of 80N on the table where it is kept Calculated the pressure by the box
Answers
Answered by
14
The force exerted by the box = 80 N
So,
. The thrust will be = 80 N
Also,
The cubical box has side of 20 cm
And,
The area will be side²
So,
Area = (20)² = 400 cm²
Now,
The pressure = thrust/area
So,
Pressure = 80/400 = 1/5 = 0.2 pascals
Hence
The pressure exerted is 0.2 Pa
So,
. The thrust will be = 80 N
Also,
The cubical box has side of 20 cm
And,
The area will be side²
So,
Area = (20)² = 400 cm²
Now,
The pressure = thrust/area
So,
Pressure = 80/400 = 1/5 = 0.2 pascals
Hence
The pressure exerted is 0.2 Pa
Answered by
14
Answer: 2000 pa
Explanation:
We know that : P = FORCE / AREA ( M^2)
FORCE = 80 N
AREA = 20^2/100*100 ( FOR M^2)
AREA = 0.04 M^2
P = 80/0.04
ON CALCULATING
WE GET
PRESSURE = 2000 PA
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