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When it is connected by wire, all charge from inside is conducted to the outer shell.
And then potential inside the shell is a constant and equal to the potential at the surface i.e kQ/b
kQ/a = V So, Q = Va/K
So, New Potential = k(Va/k)/b = Va/b
I HOPE IT WILL HELP YOU DEAR
THANKU
And then potential inside the shell is a constant and equal to the potential at the surface i.e kQ/b
kQ/a = V So, Q = Va/K
So, New Potential = k(Va/k)/b = Va/b
I HOPE IT WILL HELP YOU DEAR
THANKU
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