Question

O 4. For the reaction N2 + 202 2N02
the equilibrium concentrations in a 1.5 L reaction
vessel are 5.0 mol of N,, 7.0 mol of O, and 0.10 mol
of NO, at a certain temperature. Calculate the
equilibrium constant.​

Answer 1

Answer:

Calculate the value of the equilibrium constant for the reaction below if there are present at equilibrium 5.0 mol of N

2

, 7.0 mol of O

2

, and 0.10 mol of NO

2

in a 1.5 L vessel at a certain temperature.

N

2

+2O

2

→2NO

2

+heat

Answer 2

Answer:

6.12×10−5

Solution :

K=[NO2]2[N2][O2]

[NO2]=0.101.5,[N2]=5.01.5,[O2]=7.01.5

K=(0.101.5)2((5.01.5)(7.01.5))2=6.12×10−5

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