Question

O A father is 7 times as old as his son. Two years ago
the father was 13 times as old as his own son.
What are their present ages?​

Answer 1

$28$

$hope \: this \: helps$

Answer 2

Answer:

Son's age=x, father's age =7x

2years ago, they were

Step-by-step explanation:

dad=(7x-2) and the son =x-2

2years ago they were:

dad=(7x-2) and the son =(x-2)

So we have:

7x-2=13(x-2)

7x-2=13x-26

7x-13x=-26+2

-6x=-24

x=-24/-6

x=4 ,the age of son now

7x=7×4=28, the age of father now

PROOF:

7×4-2=13(4-2)

28-2=52-26

26=26