Question

o calculate
of zock.
no of molecules present in 5.5 moles of zncl2​

Answer 1

Given:-

• Name of Compund = $\rm{Zncl_{2}}$

• Number of mole = 5.5

To Find :-

• No. of molecule in 5.5mole of in given Compund.

Formulae used:-

• No. of molecule = Mole × Avagardo Constant

Now,

→ No. of mole = 5.5

→ Avagardo Constant = 6.022 × 10²³

→ No. of molecule = 5.5 × 6.022 × 10²³

→ No. of molecule = 33.121 × 10²³

Hence, The 5.5 mole of $\rm{Zncl_{2}}$ Contains 33.121 × 10²³ no. of molecule.

Answer 2

Given that :

Compound name : Zncl^2

Number of molecular - 5.5

To find -

No. of molecule given in 5.5mole of in Compund.

Formula used in the question is :

No. of molecule = Mole × Avagardo Constant

Now,

==} No. of molecular = 5.5

==} Avagardo Constant = 6.022 × 10²³

==} Number. of molecule = 5.5 × 6.022 × 10²³

==} Number. of molecule = 33.121 × 10²³

Hence, The 5.5 mole of Zncl^2 contains the 33.121 × 10²³ The of molecule.