Question

- o.
Find
the
Leevative
of
(x2+1) Cosx​

Answer 1

Answer:

$2xcosx-x^{2} sinx -sinx$

Step-by-step explanation:

applying product rule

$\frac{d}{dx} (x^{2} +1)cosx=\\(\frac{d}{dx} (x^{2}+1)) * cosx + (\frac{d}{dx}cosx) * (x^{2}+1)= \\(2x)cosx + (-sinx)(x^{2} +1)=\\2xcosx-x^{2} sinx -sinx$