Question

O From a square piece of an aluminium sheet of side 6cm, two
circles of radius 2cm are cut. What is the area of the left over
aluminium sheet?​

Answer 1

Answer:

Area of square =s²

Here s= 6cm

So, s²=(6)²= 36cm²

Area of circle = πr²

Here r= 2cm

So, πr²= 22/7×(2)²

= 12.57cm²(approx)

So,

Area of square - Area of circle = Leftover sheet

→ 36- 12.57 = 23.43cm²(approx)

Answer 2

☆Question

From a square piece of an aluminium sheet of side 6cm, two

circles of radius 2cm are cut. What is the area of the left over

aluminium sheet?

$</p><p>Area \: of \: the \: left \: over \: aluminium \: sheet</p><p>\green {= 23.44\: cm^{2}}=23.44cm2$

$Step-by-step \: explanation:</p><p>\begin{gathered}Side \: of \: a \: square \:piece \:of \:an \\aluminium \: sheet (a) = 6\:cm \end{gathered}$

$Side \: of \: a \: square \: piece \: of \: an \: aluminium \: sheet(a)=6cm</p><p>\boxed { \pink {Area \:of \:a \:square = a^{2}}}$

$Radius \: of \: a \:circle (r) = 2\:cmRadius \: of \: a \: circle(r)=2cm</p><p>\boxed {\orange { Area \:of \:a \:Circle = \pi r^{2}}}$

$Area \: of \: a \: Circle \: =πr2</p><p> \\ \\ /* According \: to \: the \: problem given</p><p>Area \:of \:the \: left \:over \: aluminium\:sheetAreaoftheleftoveraluminiumsheet</p><p>= Area \: of \:the \:square - Area \:of \:the \: circle=Areaofthesquare−Areaofthecircle</p><p>\begin{gathered} = a^{2} - \pi r^{2}\\= 6^{2} - 3.14 \times 2^{2}\\= 36 - 3.14 \times 4\\= 36 - 12.56\\= 23.44\: cm^{2}\end{gathered}=a2−πr2=62−3.14×22=36−3.14×4=36−12.56=23.44cm2</p><p>Therefore.,</p><p>\red{Area \:of \:the \: left \:over \: aluminium\:sheet}Areaoftheleftoveraluminiumsheet</p><p>\green {= 23.44\: cm^{2}}=23.44cm2$

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