O in the center
Find angle PQB
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In a triangle PQOB
In ∆OQB,
angle QOB + angle OQB + angle QBO = 180
angle OQB = angle QBO. ........(OQ = OB=radius)
90 + 2angle OQB = 180
2 angle OQB =90
angle OQB = 45
angle OQB= angle PQB = 45.
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