O is a point inside a rhombus ABCD such that BO = DO.
Prove that AO and CO are in the same straight Line.
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In triangle aob and cob
ab=bc (in a rhombus all sides are equal)
ob=ob (common side)
ANG. aob= ANG. cob=90°
therefore by rhs congruency the triangles are equal
cpct= ao=co
ab=bc (in a rhombus all sides are equal)
ob=ob (common side)
ANG. aob= ANG. cob=90°
therefore by rhs congruency the triangles are equal
cpct= ao=co
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