O is a point on the ground chosen as origin. A body first suffers a displacement of 10√2 m North-East, next 10 m north and finally Northwest. How far it is from the origin?
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Answered by
33
Hii dear,
# Answer- 30 m
# Explaination-
Looking at the diagram, body moves in directions A-B-C-D.
Now, we know,
AB = 10√2 m
BC = 10 m
CD = 10√2 m
sin 45 = l1/AB
1/√2 = l1/10√2
l1 = 10 m
l2 = BC = 10 m
sin 45 = l3/CD
1/√2 = l3/10√2
l3 = 10 m
Total distance = l1+l2+l3
l = 10+10+10 = 30 m
Hope this is helpful...
# Answer- 30 m
# Explaination-
Looking at the diagram, body moves in directions A-B-C-D.
Now, we know,
AB = 10√2 m
BC = 10 m
CD = 10√2 m
sin 45 = l1/AB
1/√2 = l1/10√2
l1 = 10 m
l2 = BC = 10 m
sin 45 = l3/CD
1/√2 = l3/10√2
l3 = 10 m
Total distance = l1+l2+l3
l = 10+10+10 = 30 m
Hope this is helpful...
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Answered by
26
Refer figure
S1= Displacement= 10 √2 due N-E
= (10i + 10 j) m
S2=10m due north = 10j
S3=10√ 2 m due N--W=-10i +10j
Final displacement= s1+s2+s3= 10i+10j+10j-10i+10j
=30j=30m due north
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