Question

O is any point in interior of ∆ABC , prove that AB+AC+BC is greater than OA+OB+OC.





PLEASE ANSWER ME FAST AND I WILL MARK IT AS BRAINLIEST......​

Answer 1

Answer:

Step-by-step explanation:

In triangles OAB,OAC and OBC

BY triangle inequality we get

Since side opposite to greater angle is greater

So

AB>OB

BC>OC

AC>OA

Adding all the three equations we get

AB+AC+BC>OA+OB+OC