Question

O is centre of the circle and angle BOA=130degree find the value of x

Answer 1

Hey!.. Here is your answer answer

Given : O is the centre of the circle
& angle BOA =130 degree.

To find : value of x

Solution : angle BOA + angle AOC = 180degree........ Angles in linear pair.

Therefore, angle AOC = 50degree.......(1)

In triangle AOC,

Angle AOC + angle OCA + angle CAO = 180degree...... Angle sum property of a triangle

Therefore, angle OCA + angle CAO = 130 degree...... (2)

Seg AO = seg OC.... Radii of a same circle

Therefore, triangle AOC is an isosceles triangle

Therefore, angle OAC =angle CAO.....(3)

angle CAO + angle CAO = 130......From (2) & (3)
2 (angle CAO) = 130 degree
Angle CAO = degree

x =65 degrees

Answer : x = 65 degree

Hope this will help you!
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