O is centre of the circle. Find the length of radius, if the chord of length 24 cm is at a distance of 9 cm from the centre of the circle.
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Given ' O ' is centre of the circle.
OM = 9 cm
Chord ( AB ) = 24 cm
Radius = OA
OM perpendicular to AB
and
OM bisects AB .
AM = AB/2 = 24/2 = 12 cm
In ∆AOM ,
<AMO = 90°
By Phythogarian theorem ,
OA² = AM² + OM²
= 12² + 9²
= 144 + 81
= 225
OA² = 225
OA = 15 cm
Therefore ,
Radius ( OA ) = 15 cm
••••
OM = 9 cm
Chord ( AB ) = 24 cm
Radius = OA
OM perpendicular to AB
and
OM bisects AB .
AM = AB/2 = 24/2 = 12 cm
In ∆AOM ,
<AMO = 90°
By Phythogarian theorem ,
OA² = AM² + OM²
= 12² + 9²
= 144 + 81
= 225
OA² = 225
OA = 15 cm
Therefore ,
Radius ( OA ) = 15 cm
••••
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