Radius of a circle with centre O is 25 cm. Find the distance of a chord from the center if the length of the chord is 48 cm.
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Given ' O ' is the centre of the circle.
Radius ( OA ) = 25 cm
Distance center to Chord = OM
Chord ( AB ) = 48 cm
OM perpendicular to AB.
and
OM bisects AB.
AM = AB/2 = 48/2 = 24 cm
In ∆OAM ,
<AMO = 90°
By Phythogarian theorem ,
OM² + AM² = OA²
OM² + 24² = 25²
OM² = 25² - 24²
OM² = ( 25 + 24 )( 25 - 24
OM² = 49
OM = 7cm
Therefore ,
Required distance = OM = 7 cm
••••
Radius ( OA ) = 25 cm
Distance center to Chord = OM
Chord ( AB ) = 48 cm
OM perpendicular to AB.
and
OM bisects AB.
AM = AB/2 = 48/2 = 24 cm
In ∆OAM ,
<AMO = 90°
By Phythogarian theorem ,
OM² + AM² = OA²
OM² + 24² = 25²
OM² = 25² - 24²
OM² = ( 25 + 24 )( 25 - 24
OM² = 49
OM = 7cm
Therefore ,
Required distance = OM = 7 cm
••••
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