Question

Radius of a circle with centre O is 25 cm. Find the distance of a chord from the center if the length of the chord is 48 cm.

Answer 1

this is answer of your question

Answer 2

Given ' O ' is the centre of the circle.

Radius ( OA ) = 25 cm

Distance center to Chord = OM

Chord ( AB ) = 48 cm

OM perpendicular to AB.

and

OM bisects AB.

AM = AB/2 = 48/2 = 24 cm

In ∆OAM ,

<AMO = 90°

By Phythogarian theorem ,

OM² + AM² = OA²

OM² + 24² = 25²

OM² = 25² - 24²

OM² = ( 25 + 24 )( 25 - 24

OM² = 49

OM = 7cm

Therefore ,

Required distance = OM = 7 cm

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