if V is the volume of cuboid of dimensions a, b, c and S is surface area, then prove
1/v=2/s(1/a+1/b+1/c)
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if V is the volume of cuboid of dimensions a, b, c and S is surface area, then prove
1/v=2/s(1/a+1/b+1/c)
or
2/s(1/a + 1/b + 1/c)= 2/2(ab+bc+ac)(1/a+1/b+1/c)
=(ab+bc+ac)(1/a+1/b+1/c)
=b+a+ab/c+bc/a+c+b+c+ac/b+a)
1/v=2/s(1/a+1/b+1/c)
or
2/s(1/a + 1/b + 1/c)= 2/2(ab+bc+ac)(1/a+1/b+1/c)
=(ab+bc+ac)(1/a+1/b+1/c)
=b+a+ab/c+bc/a+c+b+c+ac/b+a)
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