Question

O is the center of circle.AB is parallel to DC angle ABD=26 DEGREE FIND i)ANGLE DAB II)ANGLE DBC

Answer 1

Step-by-step explanation:

angle ADB = 90°

by angle sum property,

90 + 26 + ang DAB = 180

ang DAB = 180-116

= 64°

angle ABD = angle BDC = 26° (alt int angles)

angle ADB + angle BDC = angle ADC

90° + 26° = angle ADC

angle ADC = 116°

now, ABCD is a cyclic quad,

therefore,

angle ABC + angle CDA = 180°

(angle ABD + ang DBC) + angle CDA = 180°

26° + ang DBC + 116° = 180°

ang DBC = 180-142

= 38°

CHEERS!! looking forward for that brainly answer!

Answer 2

O is the center of circle. AB is parallel to DC angle ABD = 26 DEGREE

i) ANGLE DAB: 26 degrees, II) ANGLE DBC: 26 degrees.

Without a diagram, it is difficult to visualize the situation accurately, but based on the information given,

We can use some properties of parallel lines and angles in a circle to determine the required angles.

Since AB is parallel to DC,

We can infer that angle ABD and angle BDC are alternate interior angles and are therefore congruent.

i) Angle DAB: Since angle ABD is 26 degrees, and angles ABD and DAB are vertical angles, we can conclude that angle DAB is also 26 degrees.

ii) Angle DBC: As we noted above, angle ABD and angle BDC are congruent.

Since AB is parallel to DC, angle ABD and angle CBD are also alternate interior angles, and therefore congruent.

Thus, we can conclude that angle DBC is also 26 degrees.

In summary, angle DAB and angle DBC are both 26 degrees.

For similar questions on circle,

https://brainly.in/question/2073641

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