O is the center of the circle,and length of the chord is 8 cm seg OP chord AB If length (OP) =3 cm then find radius of the circle.by
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Given : O is the center of the circle, and length of the chord AB is 8 cm
OP ⊥ AB
length of OP = 3 cm
To Find : Radius of the circle
Solution:
AB is the chord
O is center of circle
OP ⊥ AB
Hence P is mid point of AB
=> AP = BP = AB/2 = 8/2 = 4 cm
OP = 3cm
Applying Pythagorean theorem
OA² = OP² + AP²
=> OA² = 3² + 4²
=> OA² = 25
=> OA = 5 cm
Radius of circle = 5 cm
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