Question

O is the center of the circle chord ab subtends angle 60 at centre of the circle oa= 5cm find the lenght of chord ab

Answer 1

Heya User,

--> Let the Triangle Bound between the two radii and the chord be OAB

=> OA = OB = radius 

Now, this implies that OAB is an isosceles Triangle
=> Angle OAB = Angles OBA

Given, AOB = 60°

=> Base Angles = ( 180° - 60² ) / 2 = 120°/2 = 60°

Hence we see, this is an equilateral Triangle
=> OA = OB = AB = 5cm √√