Math, asked by mahwish270603, 11 months ago

O is the centre of a circle. If tangent PQ = 12 cm and BQ = 8 cm, then chord AB is equal to :
(a) 10 cm
(b) 4 root 5 cm
(c) 4 cm
(d) 18 cm
PLS ANSWER THIS QUESTION WITH COMPLETE STEPS!!

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Answers

Answered by art12343
10
option D is the right answer.

explanation :

in the given circle -

PQ is a tangent and AQ is a secant.

PQ^2 = AB × BQ. ............tangent secant
segment
theorem

12^2 = AB × 8

144 = AB × 8

144/8 = AB

18 = AB

AB = 18 cm
Answered by kushalagarwal2711
9

Answer:

10cm

Step-by-step explanation:

In the circle,

PQ is tangent and AQ is secant

PQ^2 = BQ(AB+BQ)

144=8(AB+8)

144=8AB+64

144-64=8AB

80=8AB

Thus,

AB=10cm

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