O is the centre of a circle. If tangent PQ = 12 cm and BQ = 8 cm, then chord AB is equal to :
(a) 10 cm
(b) 4 root 5 cm
(c) 4 cm
(d) 18 cm
PLS ANSWER THIS QUESTION WITH COMPLETE STEPS!!
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Answered by
10
option D is the right answer.
explanation :
in the given circle -
PQ is a tangent and AQ is a secant.
PQ^2 = AB × BQ. ............tangent secant
segment
theorem
12^2 = AB × 8
144 = AB × 8
144/8 = AB
18 = AB
AB = 18 cm
explanation :
in the given circle -
PQ is a tangent and AQ is a secant.
PQ^2 = AB × BQ. ............tangent secant
segment
theorem
12^2 = AB × 8
144 = AB × 8
144/8 = AB
18 = AB
AB = 18 cm
Answered by
9
Answer:
10cm
Step-by-step explanation:
In the circle,
PQ is tangent and AQ is secant
PQ^2 = BQ(AB+BQ)
144=8(AB+8)
144=8AB+64
144-64=8AB
80=8AB
Thus,
AB=10cm
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