o is the centre of a circle of radius 6 cm .A is the distance of 10 cm from a point p is taken. Two tangents PQ and PR are drawn to the circle from the point then they are of quadrilateral pqor is
(a) 60cm^2
(b) 28cm^2
(c) 48cm^2
(d) 30 cm ^2
Answers
Answered by
2
Answer:
30 cm ^2 this is correct answer
Answered by
4
Answer:
c). 48cm² is the correct answer
Step-by-step explanation:
since ∆PQO is congruent to ∆PRO.
that implies in ∆PQO, OP= 10cm , OQ=6cm
therefore, tangent is perpendicular to radius at the point of contact.
that implies PQ=√OP² - OQ² = 8cm
therefore area of ∆PQO is ½ X PQ X OQ = 24cm
therefore area of PQOR is 2 X 24= 48cm²
Similar questions