O is the centre of a circle of radius r and AB is a chord of the circle at a distance from the centre. Find the length of the chord AB.
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let O D = r OD=r O C = r 2 OC=r2 in ∠ O A C & ∠ D A C ∠OAC&∠DAC S A S ~ ∠ O A C ≅ ∠ D A C SAS~∠OAC≅∠DAC so, O A = D A OA=DA Now , in ∠ O A D ∠OAD equilateral ∠ A O D = 60 ∘ ∠AOD=60∘ ∠ C A O = ∠ B A O = 30 ∘ ∠CAO=∠BAO=30∘ sin θ = r 2 r = 1 2 sinθ=r2r=12 θ = 30 ∘ θ=30∘ AnswerRead more on Sarthaks.com - https://www.sarthaks.com/1134237/if-is-the-centre-of-circle-with-radius-and-ab-is-chord-of-the-circle-at-distance-from-then-bao
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