Math, asked by supriyakamboj97, 9 months ago

O is the centre of a circle to which pax and pby are tangents from a point p at point a and b . Q is a point on the circle such that angle qax is 49 and qby is 62 what is the measure of angle aqb

Answers

Answered by satyam2776
0

Answer:

the answer isc51 degrees

Answered by amitnrw
1

Given :  pax and pby are tangents from a point p at point a and b . Q is a point on the circle such that angle qax is 49 and qby is 62. O is center of circle

To find : measure of angle aqb

Solution:

∠qax = 49°

=> ∠paq  = 180° - 49 ° = 131°

∠qby = 62°

=  ∠pbq  = 180° - 62 ° = 118°

in Quadrilateral apbq

∠paq + ∠aqb + ∠pbq + ∠apb  = 360°

=> 131° + ∠aqb  + 118°  + ∠apb  = 360°

=> ∠aqb  + ∠apb  = 111°  Eq1

in Quadrilateral apbo

∠pao + ∠aob + ∠pbo + ∠apb  = 360°

=> 90° + ∠aob  + 90°  + ∠apb  = 360°

=> ∠aob  + ∠apb  = 180°                                              

∠aob = 2  ∠aqb  ( angle by same chord at center & arc segment )

=> 2  ∠aqb  + ∠apb  = 180°     E2

Eq2 - Eq1

=> ∠aqb  = 180° - 111°

=> ∠aqb  = 69°

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