Question

O is the centre of circle and PR=QR what is the measure of angle PQR​

Answer 1

Answer:

here is your answer

<PQR=<PRQ(isocles triangle)

<QPR=180-(40+40)

=100

<QTR=180-<QPR (sum of the opposite angles of a cyclic quadrilateral is 180)

=180-100

=80

<QOR=2 x <QTR (angle substended in the circumference is half of the angle at center)

=2 x 80

= 160

<QSR=<QPR (corresponding angles are equal)

= 100

Hope it helped you

Answer 2

Answer: 90

Step-by-step explanation:

We know, PO is the radius of the circle.

QO is the radius of the circle.

We already know that triangle POQ is isosceles as PR=QR.

Angle PQO is 60 degrees. Because the triangle is isosceles, angle OPQ is also 60 degrees.

Angle PQR is 90 degrees (triangle inscribed in a semicircle).

180 - PQR - RPQ = QRP

180 - 90 - 60 = QPR = 30

Hope it helps!