O is the centre of the circle and OA = 7 cm
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Step-by-step explanation:
ANSWER
b'
Area of the minor segment=(
360
πθ
−sin
2
θ
cos
2
θ
)r
2
=(
360
o
π90
o
−sin45
0
cos45
o
)7
2
=(
4
π
−
4
1
)49=26.25cm
2
Area of the major segment =area of the circle-area of the minor segment
=πr
2
−26.25
=154−26.25=127.75cm
2
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