Question

O is the centre of the circle of radius 13cm if AC=BC=4root13 then find tha length of the perpendicular from the centre on AC and BC​

Answer 1

Answer:

Perpendicular drawn from centre of a circle to chord bisects the chord.

AC=BC=12cm

And ∠OCB=90

∘

Thus, triangle OCB is a right angled triangle

OB=13cm.

Therefore by Pythagoras theorem

OB

2

=OC

2

+BC

2

OC

2

=OB

2

−BC

2

OC=

13

2

−12

2

OC=5cm

Step-by-step explanation:

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