o is the centre of the circle pa and pb tangents to the circle then find angle AQB
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hlo friend HERE IS UR ANSWER
Since angle APB=40
ad angle OAP and OPB = 90
Therefore angle AOB = 140. (sum of angles of quadrilateral)
We know that
angle AOB = 2angle AQB
140 = 2× AQB
140/2 = AQB
angle AQB = 70
I HOPE IT HELPS YOU PLZ
PLZ MARK IT AS A BRAINLIEST
Since angle APB=40
ad angle OAP and OPB = 90
Therefore angle AOB = 140. (sum of angles of quadrilateral)
We know that
angle AOB = 2angle AQB
140 = 2× AQB
140/2 = AQB
angle AQB = 70
I HOPE IT HELPS YOU PLZ
PLZ MARK IT AS A BRAINLIEST
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