O is the centre of the circle. The distance between P and Q is 4 cm. Find angle ROQ
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145
PO = RO (radius)
there for POR is an isosceles triangle
RPO= 35°
∠ORP+∠RPO+∠POR =180° (angle sum prop)
35°+35°+∠POR =180°
∠POR =180-70
=110°
∠POR+∠ROQ =180° (supplementary angles)
∠ROQ =180-110
=70°
there for POR is an isosceles triangle
RPO= 35°
∠ORP+∠RPO+∠POR =180° (angle sum prop)
35°+35°+∠POR =180°
∠POR =180-70
=110°
∠POR+∠ROQ =180° (supplementary angles)
∠ROQ =180-110
=70°
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Answered by
14
Answer:
70°
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