Without actually performing the long division, find if 987\10500 will have terminating or nonterminating repeating decimal expansion. Give reason for your answer.
Answers
Answered by
776
Hi,
________________________________
If a fraction , in it's lowest terms , has no other
Prime factors except 2 and 5 it can be expressed
as a terminating decimal.
________________________________________
i ) first write the fraction in it's lowest
terms for that
Write the numbers into product of prime
and find the HCF of them
987 = 3 × 7 × 47
10500 = 2 × 2 × 3 × 5 × 5 × 5 × 7
HCF of 987 and 10500 = 3 × 7 = 21
Therefore ,
Least form of the fraction = 987 / 10500
Divide numerator and denominator with HCF,
we get,
= ( 987 / 21 ) / ( 10500 / 21 )
= 47 / 500
987 / 10500 = 47 / 500
Denominator = 500
= 2^2 × 5^2
We have only 2 and 5 as factors .
Therefore ,
987 / 10500 is terminating decimal.
I hope thos helps you.
:)
________________________________
If a fraction , in it's lowest terms , has no other
Prime factors except 2 and 5 it can be expressed
as a terminating decimal.
________________________________________
i ) first write the fraction in it's lowest
terms for that
Write the numbers into product of prime
and find the HCF of them
987 = 3 × 7 × 47
10500 = 2 × 2 × 3 × 5 × 5 × 5 × 7
HCF of 987 and 10500 = 3 × 7 = 21
Therefore ,
Least form of the fraction = 987 / 10500
Divide numerator and denominator with HCF,
we get,
= ( 987 / 21 ) / ( 10500 / 21 )
= 47 / 500
987 / 10500 = 47 / 500
Denominator = 500
= 2^2 × 5^2
We have only 2 and 5 as factors .
Therefore ,
987 / 10500 is terminating decimal.
I hope thos helps you.
:)
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