Question

O is the circumcentre of the triangle ABC and OD is perpendicular on BC then prove that angle BOD is equal to angle A

Answer 1

hey friend here your answer

I hope it's help you

Mark brainiest

Answer 2

in triangle BOC and triangle COD

BO = CO (both are radius)

∠BDO=∠CDO =90°

BD is common in both triangle

so both triangle are similar

so ∠BOD=∠COD

as we know angle at the center is double of the angle of corcumferece

∠BOC=2∠BAC

⇒2∠BOD=2∠BAC (as we proved above)

⇒∠BOD=∠A

hence proved.