O केंद्र असलेल्या वर्तुळाची AB ही जीवा आहे. जीवा AB ची लांबी 8 सेमी आहे. रेख OPL जीवा AB / (OP ) = 3 सेमी असेल तर वर्तुळाची त्रिज्या काढा.
Answers
Solution :-
given that,
→ O = centre of circle .
→ Chord AB = 8 cm .
→ Line segment OP = 3 cm .
since when a line segment from centre to the chord is perpendicular to the chord , it also bisect the chord .
so,
→ AP = PB = 8/2 = 4 cm .
then, in right ∆OPB we have,
→ OB² = OP² + PB² { By pythagoras theorem .}
→ OB² = 3² + 4²
→ OB = √(9 + 16)
→ OB = √25
→ OB = 5 cm (Ans.)
therefore, radius of circle is equal to 5 cm .
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