Question

o man wishes to estimate the distance of a nearby Tower from him he stands at a point a in front of the tower c and sports a very distant object in line with ac then he walks perpendicular the AC up to be at a distance of hundred metre and and looks at 0 and see again since it is the distant object that direction BOI is practically the same as a but he finds a line of sight of C shifted from the original line of light by an angle of theta is equals to 40 degree estimate the distance of the tower C from the original position a​

Answer 1

Answer:

again" (and any subsequent words) was ignored because we limit queries to 32 words.

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A man wishes to estimate the distance of a nearby tower ... - Toppr

1 answer

He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicular to AC up to B , ...

Top answer

According to figure - tan40 = AC/AB i.e., AC = AB × tan40 = 100 × 0.8390 = 83.90 m More

Answer 2

Answer:

According to this diagram,

We have, parallax angle theta = 40°

From given diagram, AB = AC tan theta

AC = AB/tan theta

= 100 m/tan 40°

= 100 m/0.8391

= 119 m