Physics, asked by mehtaindtrd, 9 months ago

O NO:15
A quantity A appears in an equation,
Ae A/T
Pressure
B
I represent temperature, 'I frequency & boltzmann constant. Kinetic energy of a gas molecule is given
3
by KT What is the dimension of in length of b​

Answers

Answered by CarliReifsteck
1

Given function is,

B=\dfrac{a}{\beta}e^{-\frac{a b}{KT}}

B = pressure

K = boltzmann constant

T = temperature

b = length

Kinetic energy of a gas molecule is 3 by KT.

In given equation \dfrac{ab}{KT} should be dimensionless

We need to calculate the dimension of a

Using term of a

a=\dfrac{KT}{b}

Put the dimension formula

\alpha=\dfrac{ML^2T^{-2}K^{-1}\times K}{L}

\alpha=MLT^{-2}

We need to calculate the dimension of \beta

Using given function

B=\dfrac{a}{\beta}

\beta=\dfrac{a}{B}

Put the value of dimension of a and B

\beta=\dfrac{MLT^{-2}}{ML^{-1}T^{-2}}

\beta=L^2

Hence, The dimension of \beta is L².

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